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#11
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| Salmon Egg schreef: - quote - > In article <48f3b89e$0$12266$58c7af7e[at]news.kabelfoon.nl> ,
Bill, Andy only wants his magnifiers qualified, nothing more nothing> Jan <nospam[at]nospam> wrote: > > The magnification standaard for a handheld glass is the diopters devided > > by 4, period. > > This is a world wide standard industrie qualification. > > > Jan (normally Dutch spoken > This "standard" is based upon the assumption that the largest angular > view for a "normal" is obtained at a distance of 250 mm from an unaided > eye. The magnifier close to the eye, effectively brings the "object" > closer. > Bill less and if possible in a simple way. I could explain more but Andy wants it simple. If you want to calculate the magnification of the combination eye-handheldmagnifier, there is more to explain. Jan (normally Dutch spoken) |
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#10
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| On Sun 12 Oct08 15:15, GeorgeB <nospam[at]att.net> wrote in <news:u314f4168fbp5t4rr79odutct3te2nn57k[at]4ax.com> : - quote - > On Sun, 12 Oct 2008 10:08:21 +0100, Andy <andy[at]yahoo.com> wrote:
Thank you all for the info and thank you for your patience!> > I think I didn't give you enough background. My query is for a > > handheld magnifying glass. In such a case a think magnification is > > stated as a fixed value such as "x8" (although the lens position > > will determine the actual magnification that is achieved). > > > I have several of these and wanted to label them bytheir power. I > > determined the focal length by using the sun and seeing how far away > > from the lens the sharped image of the was. My example said 12 cm. > > > So you showed me that 12 cm focal length is 1/0.12 = 8.33 dioptres. > > > ISTR that 4 diopters makes one "magnification"??? OTOH I have seen > > suggestions to "add 1" to the result to get magnification. > > > Does this lens with FL of 12 cm, have a magnification of x2 or x3? > We'll assume positive (magnifying) lens here ... I believe the > diopter terminology is identical, but the definition of focal lenght > is harder to understand, and my determination method does not work > for negative lens. > First, diopter is the reciprocal of the focal length in meters ... > if you have a 2 diopter lens, its focal length is 50 cm. > Magnification ASSUMES 1x for 10" (or 250mm) focal lenght. Shorter > focal lengths are higher magnification by their ratio ... a 4x > magnifier will be 2.5" focal length; a 10x will have a FL of 1". > I don't know but one way to determine focal length. If you light an > object and create its image in focus on the opposite side of the > lens, and if the ratio is 1:1 (object and image the same size), the > object and image are 4 FL apart. SO, your 12cm FL lens, placed half > way between an object and wall that are 48cm spaced, will have a > projected image the same size. I thought I had got the hang of this so I started to do the calculations and write the result on the lens holders. First I took a small magnifier for looking at samples of cloth. It has a FL=4.7cm so I calculated as follows: 100/4.7 = 21.28 dioptres. 21.28/4 = 5.3 magnification. Then another magnifier on a stand with FL = 16cm 100/16 = 6.25 dioptres. 6.25/4 = 1.6 magnification Then a large hand held lens with FL = 28cm 100/28 = 3.57 dioptres. 3.57/4 = 0.89 magnification. Hold on. 0.89 magnification? That seems wrong as I would expect magnification values are greater than 1. QUESTION: Should I add "1"? ------------- I'm starting to think that simply marking the lenses with a "magnification value" is much harder than it seems! As an alternative I suppose I could mark FL values. However some of the lenses have got manufacture's markings on them stating their magnification, so it would seem appropriate to continue with the same convention. I just didn't expect it to be so tricky! Do I add that "1"? Does the use of "1" differ if the lens is used close up or used at a distance like these two examples: distance http://www.medimax.co.uk/acatalog/magnickel.jpg close-up http://images.orgill.com/200x200/6941637.JPG |
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#9
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| In article <48f3b89e$0$12266$58c7af7e[at]news.kabelfoon.nl> , Jan <nospam[at]nospam> wrote: - quote - > Andy schreef:
This "standard" is based upon the assumption that the largest angular> > Dave, thank you for the information. > > > I think I didn't give you enough background. My query is for a > > handheld magnifying glass. In such a case a think magnification is > > stated as a fixed value such as "x8" (although the lens position will > > determine the actual magnification that is achieved). > > > Now keep it simple for me please! > Yes sir!!! > The magnification standaard for a handheld glass is the diopters devided > by 4, period. > > > I have several of these and wanted to label them bytheir power. I > > determined the focal length by using the sun and seeing how far away > > from the lens the sharped image of the was. My example said 12 cm. > > > So you showed me that 12 cm focal length is 1/0.12 = 8.33 dioptres. > So in this case you have to call this handheld a 8.33/4= 2 times > magnifying glass, period. > This is a world wide standard industrie qualification. > Jan (normally Dutch spoken view for a "normal" is obtained at a distance of 250 mm from an unaided eye. The magnifier close to the eye, effectively brings the "object" closer. Bill -- Private Profit; Public Poop! Avoid collateral windfall! |
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#8
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| Subject: Further details on Magnification Magnification The magnification of a magnifying glass depends on where it is placed between the user's eye and the object being viewed, and the total distance between the eye and the object. Magnifying glasses are typically described in terms of their magnifying power, which is equivalent to angular magnification (this should not be confused with optical power, which is a different quantity). The magnifying power is the ratio of the sizes of the images formed on the user's retina with and without the lens.[3] For the "without" case, it is typically assumed that the user would bring the object as close to the eye as possible without it becoming blurry. This point, known as the near point, varies with age. In a young child it can be as close as 5 cm, while in an elderly person it may be as far as one or two metres. Magnifiers are typically characterized using a "standard" value of 0.25 m. The highest magnifying power is obtained by putting the lens very close to the eye and moving the eye and the lens together to obtain the best focus. The object will then typically also be close to the lens. The magnifying power obtained in this condition is MP0=1/4 $B&5(B+1, where $B&5(B is the optical power in dioptres, and the factor of 1/4 comes from the assumed distance to the near point. This value of the magnifying power is the one normally used to characterize magnifiers. It is typically denoted "m$B!_(B", where m=MP0. This is sometimes called the total power of the magnifier (again, not to be confused with optical power). Magnifiers are not always used as described above, however. It is much more comfortable to put the magnifier close to the object (one focal length away). The eye can then be a larger distance away, and a good image can be obtained very easily; the focus is not very sensitive to the eye's exact position. The magnifying power in this case is roughly MP=1/4 $B&5(B. A typical magnifying glass might have a focal length of 25 cm, corresponding to an optical power of 4 dioptres. Such a magnifier would be sold as a "2$B!_(B" magnifier. In actual use, an observer with "typical" eyes would obtain a magnifying power between 1 and 2, depending on where lens is held. An older person might obtain an actual magnifying power of 8 or more with this lens, however, due to the eye's longer near point distance. Enjoy, On Oct 13, 10:18 pm, otisbr...[at]embarqmail.com wrote: - quote - > Subject: General Equations for Optical Calculations. > Since this subject develops on sci.med.vision -- here > are the equations. > Re: Some Optical Equations for Analysis > The power of a lens in diopters. > 1 / f = P > Where > f = Focal Length in Meters > P = Power in diopters > Motivation for using "Diopter" Values: > The power of lenses can be added (within reason). > P = P1 + P2 > See the thin-lens formula for reference. > =========== > Magnifying Power (telescope) > Mag = - F / f > Where F is the focal length of the objective > f = Focal length of eye-piece. > ================ > Focal Length, Image and Object Calculations: > 1 / p + 1 / q = 1 / f > Where: > f = Focal Length of Lens > p = Object Distance to Lens > q = Image Distance to lens > > ========== > Magnification Equation > I / O = - ( q / p ) > Where: > I = Image Size > O = Object Size > p = Object Distance to Lens > q = Image Distance to lens > ============= > Combining Thin Lenses > 1 / f = 1 / f1 + 1 / f2 > Where: > f = Total focal length > f1 = First lens focal length > f2 = Second lens focal length > Enjoy, > =============== > On Oct 13, 5:07 pm, Jan <nospam[at]nospam> wrote: > > Andy schreef: > > > Dave, thank you for the information. > > > I think I didn't give you enough background. My query is for a > > > handheld magnifying glass. In such a case a think magnification is > > > stated as a fixed value such as "x8" (although the lens position will > > > determine the actual magnification that is achieved). > > > Now keep it simple for me please! > > Yes sir!!! > > The magnification standaard for a handheld glass is the diopters devided > > by 4, period. > > > I have several of these and wanted to label them bytheir power. I > > > determined the focal length by using the sun and seeing how far away > > > from the lens the sharped image of the was. My example said 12 cm. > > > So you showed me that 12 cm focal length is 1/0.12 = 8.33 dioptres. > > So in this case you have to call this handheld a 8.33/4= 2 times > > magnifying glass, period. > > This is a world wide standard industrie qualification. > > Jan (normally Dutch spoken- Hide quoted text - > - Show quoted text - |
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#7
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| Subject: General Equations for Optical Calculations. Since this subject develops on sci.med.vision -- here are the equations. Re: Some Optical Equations for Analysis The power of a lens in diopters. 1 / f = P Where f = Focal Length in Meters P = Power in diopters Motivation for using "Diopter" Values: The power of lenses can be added (within reason). P = P1 + P2 See the thin-lens formula for reference. =========== Magnifying Power (telescope) Mag = - F / f Where F is the focal length of the objective f = Focal length of eye-piece. ================ Focal Length, Image and Object Calculations: 1 / p + 1 / q = 1 / f Where: f = Focal Length of Lens p = Object Distance to Lens q = Image Distance to lens - quote - > ==========
Magnification EquationI / O = - ( q / p ) Where: I = Image Size O = Object Size p = Object Distance to Lens q = Image Distance to lens ============= Combining Thin Lenses 1 / f = 1 / f1 + 1 / f2 Where: f = Total focal length f1 = First lens focal length f2 = Second lens focal length Enjoy, =============== On Oct 13, 5:07*pm, Jan <nospam[at]nospam> wrote: - quote - > Andy schreef: > > Dave, thank you for the information. > > I think I didn't give you enough background. *My query is for a > > handheld magnifying glass. In such a case a think magnification is > > stated as a fixed value such as "x8" (although the lens position will > > determine the actual magnification that is achieved). > > Now keep it simple for me please! > Yes sir!!! > The magnification standaard for a handheld glass is the diopters devided > by 4, period. > > I have several of these and wanted to label them bytheir power. I > > determined the focal length by using the sun and seeing how far away > > from the lens the sharped image of the was. *My example said 12 cm. > > So you showed me that 12 cm focal length is 1/0.12 = 8.33 dioptres. > So in this case you have to call this handheld a 8.33/4= 2 times > magnifying glass, period. > This is a world wide standard industrie qualification. > Jan (normally Dutch spoken |
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#6
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| Andy schreef: - quote - > Dave, thank you for the information.
Yes sir!!!> I think I didn't give you enough background. My query is for a > handheld magnifying glass. In such a case a think magnification is > stated as a fixed value such as "x8" (although the lens position will > determine the actual magnification that is achieved). > Now keep it simple for me please! The magnification standaard for a handheld glass is the diopters devided by 4, period. - quote - > I have several of these and wanted to label them bytheir power. I
So in this case you have to call this handheld a 8.33/4= 2 times> determined the focal length by using the sun and seeing how far away > from the lens the sharped image of the was. My example said 12 cm. > So you showed me that 12 cm focal length is 1/0.12 = 8.33 dioptres. magnifying glass, period. This is a world wide standard industrie qualification. Jan (normally Dutch spoken |
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#5
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| Andy wrote: - quote - > On Sat 11 Oct08 08:09, Dave Martindale <davem[at]cs.ubc.ca> wrote in
Same thing:> <news:gcpjf5$sqp$2[at]swain.cs.ubc.ca> : > > Andy <andy[at]yahoo.com> writes: > > > I would like to ask the specialists a question. > > > I have a magnifying glass. I measure the focal length by seeing > > > how far away the lens is when it makes a focussed image of the > > > sun on the ground. > > > If that value is, for example, 12 cm then: > > > (a) how do I calculate the dioptre strength of the lens? > > > (b) How do I calculate the magnification? > > Dioptres are simply the reciprocal of the focal length in > > metres. So a 12 cm FL lens is 1/0.12 = 8.33 dioptres. > > > The usual formula for magnification is 250/f, where f is the > > focal length in mm. For this lens, it's about 2.1. This is > > based on a couple of assumptions: > > * With normal vision, the closest you can look at something and > > have it remain in focus is 250 mm. > > * When you use a magnifier, you place the object being viewed > > one focal length from the lens, and the virtual image your eye > > sees is at infinity. > > > Under those conditions, the angular magnification is indeed > > 250/f. > > > However, there's nothing stopping you from moving the object > > slightly closer to the lens, allowing the virtual image to move > > in from infinity to 250 mm - since you should still be able to > > focus on that. Under these conditions, the magnification is > > 250/f + 1. > > > The latter formula makes more sense for relatively long focal > > length lenses used as magnifiers. If you use a 500 mm focal > > length lens, it still provides *some* useful magnification, but > > the first magnification formula says its magnification is 0.5X. > > The second formula says 1.5X, much more reasonable. > > > Dave > Dave, thank you for the information. > I think I didn't give you enough background. My query is for a > handheld magnifying glass. In such a case a think magnification is > stated as a fixed value such as "x8" (although the lens position will > determine the actual magnification that is achieved). > Now keep it simple for me please! > I have several of these and wanted to label them bytheir power. I > determined the focal length by using the sun and seeing how far away > from the lens the sharped image of the was. My example said 12 cm. > So you showed me that 12 cm focal length is 1/0.12 = 8.33 dioptres. > ISTR that 4 diopters makes one "magnification"??? 1000/fl = diopters, given focal length in mm. 250/fl = "magnification" So, a lens with 12 cm (120 mm) fl is 8.33 D. Or, 250/120 = 2.0833 X magnifier. 8.33 / 4 = 2.0833 - quote - > OTOH I have seen
Just as Dave suggested in the earlier reply. This is a more useful> suggestions to "add 1" to the result to get magnification. figure for magnification, assuming a hand-held lens. A loupe is kept at a fixed eye distance, so the simple magnification is probably more correct. - quote - > Does this lens with FL of 12 cm, have a magnification of x2 or x3?
The answer, sadly, is "Yes"! Choose your formula, either one is"correct". For me, assuming a hand lens, I'd say 3X Dave |
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#4
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| On Sun, 12 Oct 2008 10:08:21 +0100, Andy <andy[at]yahoo.com> wrote: - quote - > I think I didn't give you enough background. My query is for a
We'll assume positive (magnifying) lens here ... I believe the diopter> handheld magnifying glass. In such a case a think magnification is > stated as a fixed value such as "x8" (although the lens position will > determine the actual magnification that is achieved). > I have several of these and wanted to label them bytheir power. I > determined the focal length by using the sun and seeing how far away > from the lens the sharped image of the was. My example said 12 cm. > So you showed me that 12 cm focal length is 1/0.12 = 8.33 dioptres. > ISTR that 4 diopters makes one "magnification"??? OTOH I have seen > suggestions to "add 1" to the result to get magnification. > Does this lens with FL of 12 cm, have a magnification of x2 or x3? terminology is identical, but the definition of focal lenght is harder to understand, and my determination method does not work for negative lens. First, diopter is the reciprocal of the focal length in meters ... if you have a 2 diopter lens, its focal length is 50 cm. Magnification ASSUMES 1x for 10" (or 250mm) focal lenght. Shorter focal lengths are higher magnification by their ratio ... a 4x magnifier will be 2.5" focal length; a 10x will have a FL of 1". I don't know but one way to determine focal length. If you light an object and create its image in focus on the opposite side of the lens, and if the ratio is 1:1 (object and image the same size), the object and image are 4 FL apart. SO, your 12cm FL lens, placed half way between an object and wall that are 48cm spaced, will have a projected image the same size. |
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#3
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| On Sat 11 Oct08 08:09, Dave Martindale <davem[at]cs.ubc.ca> wrote in <news:gcpjf5$sqp$2[at]swain.cs.ubc.ca> : - quote - > Andy <andy[at]yahoo.com> writes:
Dave, thank you for the information.> > I would like to ask the specialists a question. > > I have a magnifying glass. I measure the focal length by seeing > > how far away the lens is when it makes a focussed image of the > > sun on the ground. > > If that value is, for example, 12 cm then: > > (a) how do I calculate the dioptre strength of the lens? > > (b) How do I calculate the magnification? > Dioptres are simply the reciprocal of the focal length in > metres. So a 12 cm FL lens is 1/0.12 = 8.33 dioptres. > The usual formula for magnification is 250/f, where f is the > focal length in mm. For this lens, it's about 2.1. This is > based on a couple of assumptions: > * With normal vision, the closest you can look at something and > have it remain in focus is 250 mm. > * When you use a magnifier, you place the object being viewed > one focal length from the lens, and the virtual image your eye > sees is at infinity. > Under those conditions, the angular magnification is indeed > 250/f. > However, there's nothing stopping you from moving the object > slightly closer to the lens, allowing the virtual image to move > in from infinity to 250 mm - since you should still be able to > focus on that. Under these conditions, the magnification is > 250/f + 1. > The latter formula makes more sense for relatively long focal > length lenses used as magnifiers. If you use a 500 mm focal > length lens, it still provides *some* useful magnification, but > the first magnification formula says its magnification is 0.5X. > The second formula says 1.5X, much more reasonable. > Dave I think I didn't give you enough background. My query is for a handheld magnifying glass. In such a case a think magnification is stated as a fixed value such as "x8" (although the lens position will determine the actual magnification that is achieved). Now keep it simple for me please! I have several of these and wanted to label them bytheir power. I determined the focal length by using the sun and seeing how far away from the lens the sharped image of the was. My example said 12 cm. So you showed me that 12 cm focal length is 1/0.12 = 8.33 dioptres. ISTR that 4 diopters makes one "magnification"??? OTOH I have seen suggestions to "add 1" to the result to get magnification. Does this lens with FL of 12 cm, have a magnification of x2 or x3? |
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#2
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| Thank you. The info is a bit too theoretical for my ability. For example the info at this page is a bit tricky for me to use to simply get dioptre and magnification from focal length. http://hyperphysics.phy-astr.gsu.edu.../image.html#c1 Is there something simpler? Andy On Sat 11 Oct08 05:20, <otisbrown[at]embarqmail.com> wrote[at] - quote - > Click here: > http://hyperphysics.phy-astr.gsu.edu...pt/foclen.html > On Oct 10, 6:11*pm, Andy <a...[at]yahoo.com> wrote: > > I would like to ask the specialists a question. > > > I have a magnifying glass. I measure the focal length by seeing > > how far away the lens is when it makes a focussed image of the > > sun on the ground. > > > If that value is, for example, 12 cm then: > > > (a) how do I calculate the dioptre strength of the lens? * > > (b) How do I calculate the magnification? > |
| Tags |
| dioptre, focal, length, magnification |
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